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There were 5 friends A,B,C,D and E playing a card game. All of them had some money along with them. In the game one who loose will double the money of others. They played five rounds, A lost in first round, B in second, C in third, D in fourth and E in fifth. At the end all of them were left with 32rs each. How much money they were carrying before the game individually?

• Shyam
• 01 Jan
• 3 Answers

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• • AP
    Ankit
  • 14 Jul

  We will take this in reverse order

  At the end of 5th game

  A=32 B=32 C=32 D=32 E=32

  Before 5th game (everybody’s share will be halved and added to E)

  A=16 B=16 C=16 D=16 E=96

  Before 4th game (everybody’s share will be halved and added to D)

  A=8 B=8 C=8  D=72 E=48

  Before 3rd  game (everybody’s share will be halved and added to C)

  A=4 B=4 C=68 D=68 E=24

  Before 2nd  game (everybody’s share will be halved and added to B)

  A=2 B=66 C=34 D=18 E=12

  Before 1st  game (everybody’s share will be halved and added to A)

  A=65 B=33 C=17 D=9 E=6

   

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