What is the remainder when 38^42 is divided by 10? And how I got two answers of this one is 24 by seperate then divide then fermat little therom and other is 4 by concept of cyclicity
The remainder is 4.
The last digit of 38 is 8 and lets take a look on the increasing powers of 8. We can see that there is a repeatation after 8^4.
So basically what we have to do is to divide 42 by 4 and take out the remainder. So we can see the remaider in this case is 2. So we take 8^2 and it gives us 4 in the one's place of the required digit of 38^42.
We know that if a number with its one's digit 4 is divided by 10 the remainder is alwaays 4.
So from here we can conclude the remainder of this problem is 4.